| ⇦ | 
| ⇨ |
A condenser of capacity C is charged to a potential difference of V₁. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser to V₂ is
Options
(a) [ C (V₁² – V₂²) / L ]¹/²
(b) [ C (V₁ – V₂)² / L ]¹/²
(c) C (V₁² – V₂²) / L
(d) C (V₁ – V₂) / L
Correct Answer:
[ C (V₁² – V₂²) / L ]¹/²
Explanation:
q = CV₁ cos wt
i = dq/ dt = – ?Cv₁ sin ?t
Also, ?ￂﾲ = 1 / LC and V = V₁ cos ?t
At t = t₁, V = V₂ and i = – ?CV₁ sin ?t₁
cos ?t₁ = V₂ / V₁ (-ve sign gives direction)
Hence, i = V √(C/L) [ 1 – V₂² / V₁²) ]¹/²
= [ C (V₁² – V₂²) / L ]¹/²
Related Questions: - Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
- Assuming the sun to have a spherical outer surface of radius r
- An electron of a stationary hydrogen atom passes from the fifth energy level to
- Rutherford’s α-scattering experiment concludes that
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A and B are two vectors and θ is the angle between them ,if |A x B|=√3(A.B),the value of θ
- Assuming the sun to have a spherical outer surface of radius r
- An electron of a stationary hydrogen atom passes from the fifth energy level to
- Rutherford’s α-scattering experiment concludes that
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply