A condenser of capacity C is charged to a potential difference of V₁. The plates

⇦

⇨

A condenser of capacity C is charged to a potential difference of V₁. The plates of the condenser are then connected to an ideal inductor of inductance L. The current through the inductor when the potential difference across the condenser to V₂ is

Options

(a) [ C (V₁² – V₂²) / L ]¹/²
(b) [ C (V₁ – V₂)² / L ]¹/²
(c) C (V₁² – V₂²) / L
(d) C (V₁ – V₂) / L

Correct Answer:

[ C (V₁² – V₂²) / L ]¹/²

Explanation:

q = CV₁ cos wt
i = dq/ dt = – ?Cv₁ sin ?t
Also, ?ￂﾲ = 1 / LC and V = V₁ cos ?t
At t = t₁, V = V₂ and i = – ?CV₁ sin ?t₁
cos ?t₁ = V₂ / V₁ (-ve sign gives direction)
Hence, i = V √(C/L) [ 1 – V₂² / V₁²) ]¹/²
= [ C (V₁² – V₂²) / L ]¹/²

Related Questions:

1. A spring gun of spring constant 90 N/cm is compressed 12 cm by a ball of mass
2. Four blocks of same mass connected by cords are pulled by a force F
3. A thin circular ring of mass M and radius R rotates about an axis through its centre
4. The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
5. The momentum of a photon of energy 1 MeV in kg m/s will be

Topics: Electrostatics (146)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends