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A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy stored is
Options
(a) 25×10⁵ joule
(b) 25 joule
(c) 25×10 erg
(d) 25×10³ erg
Correct Answer:
25×10³ erg
Explanation:
Energy = (1/2) CV² = (1/2) × (2 × 10⁻⁶) × (50)²
= (2 × 10⁻⁶ × 2500) / 2 = 2500 × 10⁻⁶ J
Energy = 2500 × 10⁻⁶ × 10⁷ = 25 × 10³ erg
Related Questions: - A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
- A bar magnet of moment M and pole strength m is cut into parts of equal lengths.
- The purpose of using heavy water in nuclear reactor is
- The limiting angle of incidence for an optical ray that can be transmitted
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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