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A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy stored is
Options
(a) 25×10⁵ joule
(b) 25 joule
(c) 25×10 erg
(d) 25×10³ erg
Correct Answer:
25×10³ erg
Explanation:
Energy = (1/2) CV² = (1/2) × (2 × 10⁻⁶) × (50)²
= (2 × 10⁻⁶ × 2500) / 2 = 2500 × 10⁻⁶ J
Energy = 2500 × 10⁻⁶ × 10⁷ = 25 × 10³ erg
Related Questions: - A capacitor having a capacity of 2 μF is charged to 200V and then the plates
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- Avalanche breakdown is due to
- Magnetism of a magnet is due to
- Ist law of thermadynamics is based on
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A capacitor having a capacity of 2 μF is charged to 200V and then the plates
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- Avalanche breakdown is due to
- Magnetism of a magnet is due to
- Ist law of thermadynamics is based on
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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