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A condenser has a capacity 2 μF and is charged to a voltage of 50 V. The energy stored is
Options
(a) 25×10⁵ joule
(b) 25 joule
(c) 25×10 erg
(d) 25×10³ erg
Correct Answer:
25×10³ erg
Explanation:
Energy = (1/2) CV² = (1/2) × (2 × 10⁻⁶) × (50)²
= (2 × 10⁻⁶ × 2500) / 2 = 2500 × 10⁻⁶ J
Energy = 2500 × 10⁻⁶ × 10⁷ = 25 × 10³ erg
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
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