A common emitter amplifier is designed with n-p-n transistor (α=0.99).

A Common Emitter Amplifier Is Designed With Npn Transistor 099 Physics Question

A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be

Options

(a) 9900
(b) 99
(c) 9.9
(d) 990

Correct Answer:

990

Explanation:

Voltage gain = β × Resistance gain

β = α/(1-α) = 0.99 / (1-0.99) = 99

Resistance gain = (10 × 10³) = 10

Voltage gain = 99 × 10 = 990

Related Questions:

  1. The logic behind NOR gate is that it gives
  2. Radiofrequency choke uses core of
  3. The near point and far point of a person are 40 cm and 250 cm, respectively.
  4. The electric potential at the surface of an atomic nucleus (z=50) of radius
  5. A point performs simple harmonic oscillation of period T and the equation of motion

Topics: Electronic Devices (124)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*