| ⇦ | 
| ⇨ |
A common emitter amplifier is designed with n-p-n transistor (α=0.99). The input impedence is 1kΩ and load is 10kΩ. The voltage gain will be
Options
(a) 9900
(b) 99
(c) 9.9
(d) 990
Correct Answer:
990
Explanation:
Voltage gain = β × Resistance gain
β = α/(1-α) = 0.99 / (1-0.99) = 99
Resistance gain = (10 × 10³) = 10
Voltage gain = 99 × 10 = 990
Related Questions: - A student measures the terminal potential difference (V) of a cell
- A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
- A circular disc of radius R and thickness R/6 has moment of inertia I about an axis
- A stone thrown into still water, creates a circular wave pattern moving radially
- The phase difference between the flux linked with a coil rotating in a uniform
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A student measures the terminal potential difference (V) of a cell
- A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
- A circular disc of radius R and thickness R/6 has moment of inertia I about an axis
- A stone thrown into still water, creates a circular wave pattern moving radially
- The phase difference between the flux linked with a coil rotating in a uniform
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply