| ⇦ |
| ⇨ |
A circular disc rolls down an inclined plane. The ratio of rotational kinetic energy to total kinetic energy is
Options
(a) 1/2
(b) 1/3
(c) 2/3
(d) 3/4
Correct Answer:
1/3
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- A series combination of n₁ capacitors, each of value C₁, is charged by a source
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
- The diameter of the eye ball of a normal eye is about 2.5 cm. The power of the eye
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Kr=Iomega^2
=1÷2×1÷2MR^2×(V÷R)^2
r=1÷4MV^2——-(1)
Ke=1÷2MV^2
Kt=Kr+Ke
Kt=1÷4MV^2+1÷2MV^2
Kt=3÷4MV^2
Kr÷Kt=1÷3
=1:3