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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- A small object of uniform density rolls up a curved surface with an initial velocity
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- A lift is moving down with acceleration a.A man in the lift drops a ball
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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