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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m
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- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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