⇦ | ⇨ |
A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Find the fundamental frequency of a closed pipe if the length of air column is 42m.
- If white light is used in Young’s double slit experiment
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- The loudness and pitch of a sound note depends on
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Find the fundamental frequency of a closed pipe if the length of air column is 42m.
- If white light is used in Young’s double slit experiment
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- The loudness and pitch of a sound note depends on
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply