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A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls nor rises. The charge on the drop will be (Take the mass of the charge=9.9×10⁻¹⁵ kg and g=10 m/s²)
Options
(a) 3.3×10⁻¹⁸ C
(b) 3.2×10⁻¹⁸ C
(c) 1.6×10⁻¹⁸ C
(d) 4.8×10⁻¹⁸ C
Correct Answer:
3.3×10⁻¹⁸ C
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Galilean telescope has an objective of focal length 100 cm and magnifying power 50
- Which one of the following equations of motion represents simple harmonic motion?
- Two metal spheres of radii 0.01m and 0.02m are given a charge of 15mC and 45mC
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- The dimensional formula of Plancks’s constant and angular momentum are
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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