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A boy standing at top of a tower of 20 m height drops a stone.assuming g=10 ms⁻²,the velocity with which it hits the ground is
Options
(a) 20 m/s
(b) 40 m/s
(c) 5 m/s
(d) 10 m/s
Correct Answer:
20 m/s
Explanation:
Let, v²=u²+2gh
v= is the final velocity
u= is the initial velocity
g= is the acceleration
h= is the distance
Then, u =0
.·. v²=0²+2gh
v=√2gh
Given, g=10 m/s², h=20 m
.·. v=√2x10x20
v=20 m.
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the relation n=PV/RT, n stands for
- A particle is kept at rest at the top of a sphere of diameter 42m.When disturbed slightly
- Two capacitors 3μF and 4μF, are individually charged across a 6 V battery.
- 1 a.m.u. is equivalent to
- Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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