A body starts from rest with an acceleration of 2 m/s². After 5 second,

⇦

⇨

A body starts from rest with an acceleration of 2 m/s². After 5 second, the direction of acceleration reverses again for 5 second. The displacement is

Options

(a) 5 m
(b) 50 m
(c) 55 m
(d) 0 m

Correct Answer:

0 m

Explanation:

Body starts from rest
.·. u = 0, α = 2 m/s², t = 5 sec
S₁ = ut + 1/2 αt² = 0 х 5 + 1/2 х 2 х 5 х 5 = 25 m.
Now when the body reverse its acceleration
so S₂ = 10 х 5 – 1/2 х 2 х 5 х 5 = 50 – 25 = 25 m.
.·. Total distance travelled = 25 + 25 = 50 m.
Note : There is an error in the question. The distance being a scalar, it will be 50 m but displacement being vector, it was come back to the original position. Therefore it is zero.

Related Questions:

1. A ship A is moving westwards with a speed of 10 km/h and a ship B 100 km
2. The excitation potential of hydrogen atom in the first excited state is
3. The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
4. The potential energy of a weightless spring compressed by a distance D is proportional
5. A wire mesh consisting of very small squares is viewed at a distance

Topics: Motion in Straight Line (93)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends