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A body starts from rest with an acceleration of 2 m/s². After 5 second, the direction of acceleration reverses again for 5 second. The displacement is
Options
(a) 5 m
(b) 50 m
(c) 55 m
(d) 0 m
Correct Answer:
0 m
Explanation:
Body starts from rest
.·. u = 0, α = 2 m/s², t = 5 sec
S₁ = ut + 1/2 αt² = 0 х 5 + 1/2 х 2 х 5 х 5 = 25 m.
Now when the body reverse its acceleration
so S₂ = 10 х 5 – 1/2 х 2 х 5 х 5 = 50 – 25 = 25 m.
.·. Total distance travelled = 25 + 25 = 50 m.
Note : There is an error in the question. The distance being a scalar, it will be 50 m but displacement being vector, it was come back to the original position. Therefore it is zero.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two radioactive materials X₁ and X₂ have decay constants 5λ and λ respectively
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- By the succesive disintegration of ₉₂U²³⁸, the final product obtained is ₈₂Pb²⁰⁶, then
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Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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