⇦ | ⇨ |
A body of mass M hits normally a rigid wall with velocity V and bounces back with the same velocity. The impulse experienced by the body is
Options
(a) MV
(b) 1.5 MV
(c) 2MV
(d) zero
Correct Answer:
2MV
Explanation:
Impulse experienced by the body
= change in momentum
MV – ( – MV) = 2 MV
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle executing simple harmonic motion of amplitude 5 cm has maximum
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- In the equation y=asin(?t+kx),the dimensionals formula of ? is
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
- The maximum velocity of a particle, executing simple harmonic motion with an amplitude
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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