| ⇦ | 
| ⇨ |
A body of mass 3 kg acted upon by a constant force is displaced by S meter, given by relation S=1/3t², where t is in second. Work done by the force in2 seconds
Options
(a) 8/3 J
(b) 19/5 J
(c) 5/19 J
(d) 3/8 J
Correct Answer:
8/3 J
Explanation:
S = (1/3) t²; v = dS / dt = (2/3) t
a = d²S / dt² = 2/3
F = ma = 3 × (2/3) = 2N
Work = 2 × (1/3) t²
At t = 2 seconds
.·. Work = 2 × (1/3) × 2 × 2 = (8/3) J
Related Questions: - Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- The velocity of sound is V, in air. If the density of air is increased to four times
- Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
- In an orbital motion, the angular momentum vector is
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- The velocity of sound is V, in air. If the density of air is increased to four times
- Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
- In an orbital motion, the angular momentum vector is
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply