| ⇦ | 
| ⇨ |
A body of mass 1 kg is thrown upwards with a velocity 20 m/s. It momentarily comes to rest after attaining a height of 18 m. How much energy is lost due to air friction? (g = 10 m/s²)
Options
(a) 30 J
(b) 40 J
(c) 10 J
(d) 20 J
Correct Answer:
20 J
Explanation:
When the body is thrown upwards. its K.E is converted into P.E. The loss of energy due to air friction is the difference of K.E and P.E
1/2 mv² – mgh = 1/2 x 1 x 400 – 1 x 18 x 10
= 200 – 180 = 20 J
Related Questions:
- Which is incorrect about thermal process
- Which of the following statement about scalar quantity is true?
- A magnetic needle suspended parallel to a magnetic field requires √3J of work
- Nickel shows ferromagnetic property at room temperature. If the temperature is
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply