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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For principal quantum number n=3, the possible values of orbital quantum number
- How much work is required to carry a 6 μC charge from the negative terminal
- The fundamental frequency of a closed organ pipe of length 20 cm is equal to the second
- Diameter of the objective of a telescope is 200 cm. What is the resolving power
- In an inductor when current changes from 2 A to 18 A in 0.05 sec, the e.m.f. induced
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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