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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
Related Questions: - In a uniform circular motion,
- The quantity having the same units in all systems of unit is
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a uniform circular motion,
- The quantity having the same units in all systems of unit is
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
- An air core solenoid has 1000 turns and is one meter long. Its cross sectional area
- A particle performing uniform circular motion has angular momentum
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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