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A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻². Its apparent weight will be (g=10 ms⁻²)
Options
(a) 1.0 kg wt
(b) 2.0 kg wt
(c) zero
(d) 0.5 kg wt
Correct Answer:
zero
Explanation:
R = m (g – a) = m (10 – 10) = zero
This answer is an extension of the lift problem. Actually mg is the force acting on the mass m. As potential energy decreases, its kinetic energy increases as experienced. The question is not correct.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When photons of energy hν fall on an aluminium plate (of work function E₀),
- In an orbital motion, the angular momentum vector is
- An electric bulb has a rated power of 50W at 100 V. if it used on an a.c. source
- A force acts on a 3.0 g particle in such a way that the position of the particle
- A body with mass 5 kg is acted upon a force F=(-3i+4j) N.If its initial velocity at
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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