| ⇦ | 
| ⇨ |
A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where a= 5m⁻¹/² s⁻¹.The work done by the net force during its displacement from x=0 to x=2 m is
Options
(a) 1.5j
(b) 50 j
(c) 10 j
(d) 100 j
Correct Answer:
50 j
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- B is doped in Si or Ge, then we will get
- Surface tension of water will be minimum at
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- B is doped in Si or Ge, then we will get
- Surface tension of water will be minimum at
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply