| ⇦ |
| ⇨ |
A block of mass m is placed on a smooth wedge of inclination θ.The whole system is accelerated horizontally, so that the block does not slip on the wedge.The force exerted by the wedge on the block (g is accelerated due to gravity) will be
Options
(a) mg cos θ
(b) mg sin θ
(c) mg
(d) mg/cosθ
Correct Answer:
mg/cosθ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The phenomenon of radioactivity
- The relationship between decay constant λ and half-life T of a radioactive substance is
- For a diatomic gas charge in internal energy for unit charge in temperature for
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The phenomenon of radioactivity
- The relationship between decay constant λ and half-life T of a radioactive substance is
- For a diatomic gas charge in internal energy for unit charge in temperature for
- The vector sum of two forces is perpendicular to their vector difference. In that case,
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply