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A block of mass m is placed on a smooth wedge of inclination θ.The whole system is accelerated horizontally, so that the block does not slip on the wedge.The force exerted by the wedge on the block (g is accelerated due to gravity) will be
Options
(a) mg cos θ
(b) mg sin θ
(c) mg
(d) mg/cosθ
Correct Answer:
mg/cosθ
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The dimensional formula for Young’s modulus is
- If A.B=A x B,then the angle between A and B is
- In a vaccum triode the function of grid voltage is
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimensional formula for Young’s modulus is
- If A.B=A x B,then the angle between A and B is
- In a vaccum triode the function of grid voltage is
- The manifestation of band structure in solids is due to
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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