| ⇦ | 
| ⇨ |
A block of mass M is attached to the lower end of a vertical spring. The spring is hung from a ceiling and has force constant value k. The mass is released from rest with the spring initially unstretched. The maximum extension produced in the length of the spring will be:
Options
(a) 2 Mg/k
(b) 4 Mg/k
(c) Mg/2k
(d) Mg/k
Correct Answer:
Mg/k
Explanation:
Restoring force, f’ = – kx. where x is the extension produced in the spring.
Weight of the mass acting downward = Mg.
In equilibrium kx = Mg, x= Mg / k
Related Questions: - At what distance from the centre of earth, the value of acceleration due to gravity
- 1 a.m.u. is equivalent to
- An air bubble in a glass slab with refractive index 1.5 (near normal incidence)
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- In communication with help of antenna if height is doubled then the range
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what distance from the centre of earth, the value of acceleration due to gravity
- 1 a.m.u. is equivalent to
- An air bubble in a glass slab with refractive index 1.5 (near normal incidence)
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
- In communication with help of antenna if height is doubled then the range
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply