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A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force of 5 N acts on it for 4 sec. What will be the distance of the block from the point where the force started acting?
Options
(a) 6 m
(b) 8 m
(c) 10 m
(d) 2 m
Correct Answer:
10 m
Explanation:
Horizontal distance,x=ut ⇒1.5 x 4 = 6m
Vertical distance,y=(1/2)at² = (1/2)(F/m)t²
Two motions are in mutually perpendicular directions. Net displacement = √(6²+8²) = √(36+64) =√100 = 10m.
Related Questions: - In Young’s experiment, the third bright band for light of wavelength 6000Å
- A sound source is moving towards a stationary listener with 1/10th of the speed
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s experiment, the third bright band for light of wavelength 6000Å
- A sound source is moving towards a stationary listener with 1/10th of the speed
- A thermodynamic system undergoes cyclic process ABCDA as shown in figure
- Fission of nuclei is possible because the binding energy per nucleon in them
- When the length of the vibrating segment of a sonometer wire is increased by
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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