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A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two waves of same amplitude superpose. The resultant intensity is I₁
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- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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