| ⇦ |
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The breaking stress of a wire depends upon
- A change of 0.04 V takes place between the base and the emitter when an input
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- A particle moves in a straight line with a constant acceleration
- Charge density for intrinsic semiconductor will be
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The breaking stress of a wire depends upon
- A change of 0.04 V takes place between the base and the emitter when an input
- Two identical flutes produce fundamental notes of frequency 300 Hz at 27° C
- A particle moves in a straight line with a constant acceleration
- Charge density for intrinsic semiconductor will be
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply