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A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The current in the windings of a toroid is 2.0 A. There are 400 turns
- The dimensions of magnetic field intensity B are
- The drift velocity does not depend upon
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- The dimensions of magnetic field intensity B are
- The drift velocity does not depend upon
- A galvanometer having resistance of 50 Ω requires a current of 100μA to give full
- The de-Broglie wavelength of neutron in thermal equilibrium at temperature T is
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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