| ⇦ | 
| ⇨ |
A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field and is in equillibrium state. The energy required to rotate it by 60⁰ is W. Now the torque required to keep the magnet in this new position is
Options
(a) W/√3
(b) √3W
(c) √3W/2
(d) 2W/√3
Correct Answer:
√3W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If the feedback voltage is increased in a negative feedback amplifier, then
- A small object of uniform density rolls up a curved surface with an initial velocity
- Two coaxial solenoids are made by winding thin insulated wire over a pipe
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the feedback voltage is increased in a negative feedback amplifier, then
- A small object of uniform density rolls up a curved surface with an initial velocity
- Two coaxial solenoids are made by winding thin insulated wire over a pipe
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply