| ⇦ | 
| ⇨ |
A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal plane. A horizontal magnetic field B = 6 x 10⁻⁴T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60⁰ from the field is
Options
(a) 12 J
(b) 6 J
(c) 2 J
(d) 0.6 J
Correct Answer:
6 J
Explanation:
Work done
= MB (cos θ₁ – cos θ₂)
= MB (cos 0⁰ – cos 60⁰)
= MB (1 – 1/2) = 2 x 10⁴ x 6 x 10⁻⁴ /2 = 6 J
Related Questions: - A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- A particle of mass m is projected with a velocity v making an angle of 45°
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- The heat dissipated in a resistance can be obtained by measuring of resistance,
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A dip needle vibrates in a vertical plane perpendicular to magnetic meridian. The time
- A particle of mass m is projected with a velocity v making an angle of 45°
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- The heat dissipated in a resistance can be obtained by measuring of resistance,
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply