8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure

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8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is

Options

(a) 9
(b) 18
(c) 27
(d) 36

Correct Answer:

27

Explanation:

PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27

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Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)

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