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8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is
Options
(a) 9
(b) 18
(c) 27
(d) 36
Correct Answer:
27
Explanation:
PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bleaching powder is obtained by treating Cl₂ with
- What is formed when hydrogen atom of the -OH group in phenol is replaced by
- Schiff’s reagent is
- The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is
- The basic component of the smog is
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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