8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure

82 L Of An Ideal Gas Weight 90 Gm At Chemistry Question

8.2 L of an ideal gas weight 9.0 gm at 300 K and 1 atm pressure. The molecular mass of the gas is

Options

(a) 9
(b) 18
(c) 27
(d) 36

Correct Answer:

27

Explanation:

PV = nRT = (m / M) RT ⇒ M = mRT / PV = (9.0 × 0.0821 × 300) / (1 × 8.2) = 27

Related Questions:

  1. The two ice cubes kept pressed against each other, stick to each other due to
  2. At what pressure a gas, which occupies 100 mL at a pressure of 720 mm
  3. What is the nature of the bond between B and O in (C₂H₅)₂ OBH₃?
  4. The basic component of the smog is
  5. The species Ar,K⁺ and Ca²⁺ contain the same number of electrons.

Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*