| ⇦ | 
| ⇨ |
5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together and volume made to one litre . The normality of the resulting solution is
Options
(a) N/5
(b) N/10
(c) N/20
(d) N/40
Correct Answer:
N/40
Explanation:
5 mL of N HCl , 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed. Volume of resultant solution = V(T) = 1000 mL.
Since, N₁V₁ + N₂V₂ + N₃V₃ = N(T)V(T).
⇒ 5 ⨯N + 20 ⨯N/2 + 30 ⨯N/3 = N(T) ⨯ 1000.
⇒ 5⨯ N + 10 ⨯ N + 10 ⨯ N = 1000⨯ N(T)
⇒ N(T) = N/40.
Related Questions: - The orientation of an atomic orbital is governed by
- An example for a saturated fatty acid, present in nature is
- The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy
- Which of the following has zero valency
- The lusture of a metal is due to
Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The orientation of an atomic orbital is governed by
- An example for a saturated fatty acid, present in nature is
- The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy
- Which of the following has zero valency
- The lusture of a metal is due to
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply