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5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together and volume made to one litre . The normality of the resulting solution is
Options
(a) N/5
(b) N/10
(c) N/20
(d) N/40
Correct Answer:
N/40
Explanation:
5 mL of N HCl , 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed. Volume of resultant solution = V(T) = 1000 mL.
Since, N₁V₁ + N₂V₂ + N₃V₃ = N(T)V(T).
⇒ 5 ⨯N + 20 ⨯N/2 + 30 ⨯N/3 = N(T) ⨯ 1000.
⇒ 5⨯ N + 10 ⨯ N + 10 ⨯ N = 1000⨯ N(T)
⇒ N(T) = N/40.
Related Questions: - Amongst the elements with following electronic configurations
- For which one of the following equations is ΔH⁰react equal to ΔH°f
- Identify the correct order of the size of the following elements:
- Which one of the following has ΔS⁰ greater then zero
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Topics: Solid State and Solutions
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Amongst the elements with following electronic configurations
- For which one of the following equations is ΔH⁰react equal to ΔH°f
- Identify the correct order of the size of the following elements:
- Which one of the following has ΔS⁰ greater then zero
- n-Butane and isobutane are
Topics: Solid State and Solutions (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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