| ⇦ | 
| ⇨ |
300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure. The final volume is
Options
(a) 350 L
(b) 270 mL
(c) 540 L
(d) 135 mL
Correct Answer:
270 mL
Explanation:
At constant pressure V₁ / T₁ = V₂ / T₂ (Charle’s law)
T₁ = 27°C = 27 + 273 = 300 K
T₂ = -3°C = -3 + 273 = 270K
V₂ = V₁T₂ / T₁ = (300 × 270) / 300 = 270 mL
Related Questions: - What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO₃
- Dialysis can separate
- Which one of the following elements constitutes a major impurity in pig iron
- Which of the following is true about ClO₂
- Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the mass of the precipitate formed when 50 mL of 16.9% solution of AgNO₃
- Dialysis can separate
- Which one of the following elements constitutes a major impurity in pig iron
- Which of the following is true about ClO₂
- Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Acc to Charle’s law V1T2= V2 T1
V=300 ml
T1=27°C=27+273K=300K
V2=?
T2= 273-3°C=270K
V1T2= V2T1
300×270=V2×300
V2=270ml