| ⇦ | 
| ⇨ |
300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure. The final volume is
Options
(a) 350 L
(b) 270 mL
(c) 540 L
(d) 135 mL
Correct Answer:
270 mL
Explanation:
At constant pressure V₁ / T₁ = V₂ / T₂ (Charle’s law)
T₁ = 27°C = 27 + 273 = 300 K
T₂ = -3°C = -3 + 273 = 270K
V₂ = V₁T₂ / T₁ = (300 × 270) / 300 = 270 mL
Related Questions: - Which of the following carbonyls will have the strongest C – O bond
- Dumas method is used for the estimation of
- Which of the following is not a transition metal
- Rate determining step in nitration of bezene is
- Which of the following statement about the member of any one homologous series
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following carbonyls will have the strongest C – O bond
- Dumas method is used for the estimation of
- Which of the following is not a transition metal
- Rate determining step in nitration of bezene is
- Which of the following statement about the member of any one homologous series
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Acc to Charle’s law V1T2= V2 T1
V=300 ml
T1=27°C=27+273K=300K
V2=?
T2= 273-3°C=270K
V1T2= V2T1
300×270=V2×300
V2=270ml