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300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure. The final volume is
Options
(a) 350 L
(b) 270 mL
(c) 540 L
(d) 135 mL
Correct Answer:
270 mL
Explanation:
At constant pressure V₁ / T₁ = V₂ / T₂ (Charle’s law)
T₁ = 27°C = 27 + 273 = 300 K
T₂ = -3°C = -3 + 273 = 270K
V₂ = V₁T₂ / T₁ = (300 × 270) / 300 = 270 mL
Related Questions: - Aluminium is obtained by
- In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
- Which one of the following statements about halogens is correct
- Two miscible liquids can be separated by
- In a buffer solution containing equal concentration of B⁻ and HB,
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Aluminium is obtained by
- In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
- Which one of the following statements about halogens is correct
- Two miscible liquids can be separated by
- In a buffer solution containing equal concentration of B⁻ and HB,
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Acc to Charle’s law V1T2= V2 T1
V=300 ml
T1=27°C=27+273K=300K
V2=?
T2= 273-3°C=270K
V1T2= V2T1
300×270=V2×300
V2=270ml