| ⇦ |
| ⇨ |
300 mL of a gas at 27⁰C is cooled to -3⁰C at constant pressure. The final volume is
Options
(a) 350 L
(b) 270 mL
(c) 540 L
(d) 135 mL
Correct Answer:
270 mL
Explanation:
At constant pressure V₁ / T₁ = V₂ / T₂ (Charle’s law)
T₁ = 27°C = 27 + 273 = 300 K
T₂ = -3°C = -3 + 273 = 270K
V₂ = V₁T₂ / T₁ = (300 × 270) / 300 = 270 mL
Related Questions: - Which one of the following has ΔS⁰ greater then zero
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
- A substance with initial concentration of a mol dm⁻³ follows zero order kinetics.
- Which of the following statement about the member of any one homologous series
- If uncertainty in position and momentum are equal, then uncertainty in velocity
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following has ΔS⁰ greater then zero
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
- A substance with initial concentration of a mol dm⁻³ follows zero order kinetics.
- Which of the following statement about the member of any one homologous series
- If uncertainty in position and momentum are equal, then uncertainty in velocity
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Acc to Charle’s law V1T2= V2 T1
V=300 ml
T1=27°C=27+273K=300K
V2=?
T2= 273-3°C=270K
V1T2= V2T1
300×270=V2×300
V2=270ml