1 c.c N₂O at NTP contains

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1 c.c N₂O at NTP contains

Options

(a) (1.8/224) x 10²² atoms
(b) (6.02/22400) x 10²³ molecules
(c) (1.32/224) x 10²³ electrons
(d) all the above

Correct Answer:

all the above

Explanation:

At N.T.P 22400 cc of N₂O =6.02 x 10²³ molecules
1 cc contains = (6.02 x 10²³) / 22400 molecules

N₂O contains 3 atoms, so
= (3 x 6.02 x 10²³) / 22400 atoms
=1.8 / 224 x 10²² atoms

No of electrons in N₂O = (7*2)+8  =22

= (22 x 6.02 x 10²³) / 22400 electrons

=132.44 x 10²³ / 22400 electrons

=1.32 x 10²³ / 224 electrons

Related Questions:

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Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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