| ⇦ |
| ⇨ |
1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Options
(a) 1.52
(b) 0.995
(c) 190
(d) 9
Correct Answer:
9
Explanation:
One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g
Similarly, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.
Let E be the equivalent mass of the metal. And let x be the number of equivalents of metal hydroxide ignited.
Therefore,
x(E+17) = 1.520g and
x(E+8) = 0.995
Eliminating x, we get E=9.06g.
Related Questions: - The oxidation state of nitrogen is highest in
- In the following reaction, the product(A)
- Which of the following compound react with NaHCO3 solution to give sodium salt
- In which of the following reaction, the hydrogen peroxide is a reducing agent?
- The reaction CH₃ – Br + 2Na + Br – CH₃ → CH₃ – CH₃ is called
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation state of nitrogen is highest in
- In the following reaction, the product(A)
- Which of the following compound react with NaHCO3 solution to give sodium salt
- In which of the following reaction, the hydrogen peroxide is a reducing agent?
- The reaction CH₃ – Br + 2Na + Br – CH₃ → CH₃ – CH₃ is called
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply