1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide

1520 G Of Hydroxide Of A Metal On Ignition Gave Chemistry Question

1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is

Options

(a) 1.52
(b) 0.995
(c) 190
(d) 9

Correct Answer:

9

Explanation:

One equivalent of the metal reacts with one mole of hydroxide, i.e., 17g

Similarly, one equivalent of the metal reacts with 1/2 mole oxygen atoms, i.e., 8g of oxygen atoms.

Let E be the equivalent mass of the metal. And let x be the number of equivalents of metal hydroxide ignited.

Therefore,

x(E+17) = 1.520g and

x(E+8) = 0.995
Eliminating x, we get E=9.06g.

Related Questions:

  1. Equal volumes of methanoic acid and sodium hydroxide are mixed, if x is the heat
  2. K₃[Al (C₂O₄)₃] is called
  3. Hexoses and pentoses are
  4. 5 mL of N HCl, 20 mL of N/2 H₂SO₄ and 30 mL of N/3 HNO₃ are mixed together
  5. For the reaction C₂H₅OH + 3O₂(g) → 2CO₂(g) + 3H₂O which one is true

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*