| ⇦ | 
| ⇨ |
0.037g of an alcohol, R-OH was added to C₂H₅Mgl and the has evolved measured 11.2cc at STP. The molecular mass of R-OH will be
Options
(a) 47
(b) 79
(c) 77
(d) 74
Correct Answer:
74
Explanation:
R—OH + C₂H₅Mgl → C₂H₆ + RMgl
0.037 11.2 cc
11.2 cc gas evolved by alcohol= 0.037 g
22400 cc gas will be evolved by alcohol
= 0.037/11.2 x 22400
= 74 g
Related Questions: - The pH of solution containing 0.10 M sodium acetate and 0.03 M acetic acid is
- The combustion enthalpies of carbon , hydrogen and methane are -395.5 kJ mol⁻¹
- The electronegativity of the following elements increases in the order.
- Dihedral angle in staggered form of ethane is
- In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pH of solution containing 0.10 M sodium acetate and 0.03 M acetic acid is
- The combustion enthalpies of carbon , hydrogen and methane are -395.5 kJ mol⁻¹
- The electronegativity of the following elements increases in the order.
- Dihedral angle in staggered form of ethane is
- In HS⁻, I⁻, R-NH₂, NH₃ order of proton accepting tendency will be
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply