| ⇦ |
| ⇨ |
λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe widths. The wavelength λ₁ can produce photoelectric effect when incident on a metal. But the wavelength λ₂ cannot produce photoelectric effect. The correct relation between β₁ and β₂ is
Options
(a) β₁ < β₂
(b) β₁ = β₂
(c) β₁ > β₂
(d) β₁ ≥ β₂
Correct Answer:
β₁ < β₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Curie temperature above which
- An LED is constructed from a p-n junction based on a certain semi-conducting
- Unit of reduction factor is
- The electric field at a distance 3R / 2 from the centre of a charged conducting
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Curie temperature above which
- An LED is constructed from a p-n junction based on a certain semi-conducting
- Unit of reduction factor is
- The electric field at a distance 3R / 2 from the centre of a charged conducting
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply