Which of the following coordination compounds would exhibit optical isomerism
Options
(a) Pentaamminenitrocobalt (III) iodide (b) Diamminedichloroplatinum(II) (c) Trans-dicyanobis(ethylenediamine) chromium(III) chloride (d) Tris-(ethylenediamine)cobalt(III) bromide
Correct Answer:
Tris-(ethylenediamine)cobalt(III) bromide
Explanation:
No explanation available. Be […]
The ion which is not tetrahedral in shape is
Options
(a) BF₄⁻ (b) NH₄⁺ (c) Cu(NH₃)₄²⁺ (d) NiCl₄²⁻
Correct Answer:
Cu(NH₃)₄²⁺
Explanation:
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According to IUPAC nomenclature sodium nitroprusside is named as
Options
(a) sodium nitroferricyanide (b) sodium nitroferrocyanide (c) sodium pentacyanonitrosyl ferrate (II) (d) sodium pentacyanonitrosyl ferrate (III)
Correct Answer:
sodium pentacyanonitrosyl ferrate (II)
Explanation: […]
dsp² hybridisation is found in
Options
(a) [NiCl₄]²⁻ (b) [CoCl₄]²⁻ (c) [CuCl₄]³⁻ (d) [CuCl₄]²⁻
Correct Answer:
[CoCl₄]²⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by […]
In the silver plating of copper, K[Ag(CN)₂] is used instead of AgNO₃. The reason is
Options
(a) a thin layer of Ag is formed on Cu (b) more voltage is required (c) Ag⁺ […]
In the formation of [Ni(CN)₄]²⁻, the type of hybridisation involved is
Options
(a) sp² (b) sp³d (c) dsp² (d) sp³d
Correct Answer:
dsp²
Explanation:
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Which of the following will exhibit maximum ionic conductivity?
Options
(a) K₄[Fe(CN)₆] (b) [Co(NH₃)₆]Cl₃ (c) [Cu(NH₃)₄]Cl₂ (d) [Ni(CO)₄]
Correct Answer:
K₄[Fe(CN)₆]
Explanation:
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CuSO₄ dissolves in NH₃ due to the formation of
Options
(a) Cu(OH)₂ (b) Cu[(NH₃)₄]SO₄ (c) Cu[(NH₃)₄(OH)₂] (d) CuO
Correct Answer:
Cu[(NH₃)₄(OH)₂]
Explanation:
NH₃+ H₂O→ NH₄OH CuSO₄ + NH₄OH → Cu(OH)₂ + (NH₄)₂ SO₄ […]
Shape of Fe(CO)₅ is
Options
(a) Octahedral (b) square planar (c) trigonal bipyramidal (d) square pyramidal
Correct Answer:
trigonal bipyramidal
Explanation:
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How many edta molecules can surround calcium
Options
(a) 2 (b) 1 (c) 3 (d) 8
Correct Answer:
1
Explanation:
No explanation available. Be the first to write the explanation for this question […]
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