The horizontal range and maximum height of a projectile are equal.The angle of projection
The horizontal range and maximum height of a projectile are equal.The angle of projection is
Options
(a) θ=tan⁻¹(1/4) (b) θ=tan⁻¹(4) (c) θ=tan⁻¹(2) (d) θ=45゚
Correct Answer:
θ=tan⁻¹(4)
Explanation:
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