| ⇦ | 
| ⇨ |
The number of photons of wavelength of 540 nm emitted per second by an electric bulb of power 100 W is (given h=6×10⁻³⁴ J-s)
Options
(a) 100
(b) 1000
(c) 3×10²⁰
(d) 3×10¹⁸
Correct Answer:
3×10²⁰
Explanation:
Power = nhc / ( × t)
⇒ 100 = [n × (6 × 10⁻³⁴) × (3 × 10⁸)] / (540 × 10⁹ × 1)
⇒ n × 18 × 10⁻²⁶ / 540 × 10⁻⁹ = 100
⇒ n = 100 × 540 × 10⁻⁹ / 18 × 10⁻²⁶ = 3 x 10²⁰
Related Questions: - Eight drops of a liquid of density ρ and each of radius a are falling through air
- Two identical capacitors are first connected in series and then in parallel.
- The coefficient of performance of a Carnot refrigerator working between 30⁰C and 0⁰C is
- Dimensions of electrical resistance are
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Eight drops of a liquid of density ρ and each of radius a are falling through air
- Two identical capacitors are first connected in series and then in parallel.
- The coefficient of performance of a Carnot refrigerator working between 30⁰C and 0⁰C is
- Dimensions of electrical resistance are
- A body of mass M hits normally a rigid wall with velocity V and bounces back
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply