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What is the energy of photon whose wavelength is 6840 Å?
Options
(a) (1.81 eV)
(b) (3.6 eV)
(c) (-13.6 eV)
(d) (12.1 eV)
Correct Answer:
(1.81 eV)
Explanation:
λ = 6840 Å
.·. ʋ = c / λ ⇒ hʋ = hc / λ
If hc = 12400 eV Å
Energy of the photon = 12400eV Å / 6840 Å
= 1.81 Å
Related Questions: - In a circuit, the current lags behind the voltage by a phase difference of π/2.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a circuit, the current lags behind the voltage by a phase difference of π/2.
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- The horizontal and vertical components of earth’s magnetic field at a place
- The moment of inertia of a semicircular ring about the centre is
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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