| ⇦ |
| ⇨ |
In potentiometer experiment, a cell of emf 1.25V gives balancing length of 30 cm. If the cell is replaced by another cell, then balancing length is found to be 40cm. What is the emf of second cell?
Options
(a) ≈1.5V
(b) ≈1.67V
(c) ≈1.47V
(d) ≈1.37V
Correct Answer:
≈1.67V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- A capacitor of capacitance value 1 μF is charged to 30 V and the battery
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
- The horizontal range and maximum height attained by a projectile are R and H,respectively
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply