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In Wheatstone bridge, three resistors P,Q and R are conncected in three arms in order and 4th arm of resistance s, is formed by two resistors s₁ and s₂ connected in parallel. The condition for bridge to be balanced is, P/Q
Options
(a) R(s₁+s₂)/s₁s₂
(b) s₁s₂/R(s₁+s₂)
(c) R(s₁s₂)/(s₁+s₂)
(d) (s₁+s₂)R(s₁s₂)
Correct Answer:
R(s₁+s₂)/s₁s₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- If a proton, a deuteron and an alpha particle, on being accelerated by the same
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- A body undergoes no change in volume. Poisson’s ratio is
- A car moves from X to Y with a uniform speed v(u) and returns to Y with a uniform speed
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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