| ⇦ | 
| ⇨ |
If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV respectively, then in the reaction: p+₃⁷Li→2 ₂⁴He, energy of proton must be
Options
(a) 39.2 MeV
(b) 28.24 MeV
(c) 17.28 MeV
(d) 1.46 MeV
Correct Answer:
17.28 MeV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - P-type semiconductors are made by adding impurity element
- 1 a.m.u. is equivalent to
- Bohr’s postulates quantizes
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- The given graph represents V-I characteristic for a semiconductor device
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- P-type semiconductors are made by adding impurity element
- 1 a.m.u. is equivalent to
- Bohr’s postulates quantizes
- The rms current in an AC circuit is 2 A. If the wattless current be √3 A,
- The given graph represents V-I characteristic for a semiconductor device
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply