⇦ | ⇨ |
The wavelength of the first line of Lyman series for hydrogen atom is equal to that of the second line of Balmer series for a hydrogen like ion. The atomic number Z of hydrogen like ion is
Options
(a) 3
(b) 4
(c) 1
(d) 2
Correct Answer:
2
Explanation:
For first line of Lyman series of hydrogen
hc/λ₁ = Rhc (1/1² – 1/2²)
For second line of Balmer series of hydrogen like on
hc/λ₂ = Z²Rhc (1/2² – 1/4²)
By eq. λ₁ = λ₂
(1/1 – 1/2) = Z² (1/4 – 1/16) or Z = 2
Related Questions: - A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- If doubly ionised lithium atom is hydrogen like with atomic number 3, the wavelength
- The total energy of a simple harmonic oscillator is proportional to
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- A particle of mass 1mg has the same wavelength as an electron moving with a velocity
- If doubly ionised lithium atom is hydrogen like with atomic number 3, the wavelength
- The total energy of a simple harmonic oscillator is proportional to
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply