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The ratio of speed of an electron in ground state in Bohr’s first orbit of hydrogen atom to velocity of light in air (c ) is
Options
(a) e²/2ε₀hc
(b) 2e²ε₀/hc
(c) e³/2ε₀hc
(d) 2ε₀hc/e²
Correct Answer:
e²/2ε₀hc
Explanation:
Velocity of electron in nᵗʰ orbit = αcz / n
where α = (e²/4πε₀) [1 / c(h/π)] = e²/2ε₀hc
v / c = αz / n = (e² × 1) / 2ε₀hc × 1 = e²/2ε₀hc
Related Questions: - A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- For a thermocouple, the neutral temperature is 270⁰C when its cold junction is at 20⁰C.
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
- The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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