| ⇦ | 
| ⇨ |
An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is
Options
(a) 3
(b) 4
(c) 5
(d) 2
Correct Answer:
4
Explanation:
KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.
Related Questions: - If the electric field lines is flowing along axis of a cylinder, then the flux
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The distance travelled by a particle starting from rest and moving with an acceleration
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- Four blocks of same mass connected by cords are pulled by a force F
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the electric field lines is flowing along axis of a cylinder, then the flux
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- The distance travelled by a particle starting from rest and moving with an acceleration
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- Four blocks of same mass connected by cords are pulled by a force F
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply