| ⇦ | 
| ⇨ |
An alpha nucleus of energy 1/2 mv² bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to
Options
(a) 1 / Ze
(b) v²
(c) 1 / m
(d) 1 / v⁴
Correct Answer:
1 / m
Explanation:
Kinetic energy of alpha nucleus is equal to electrostatic potential energy of the system of the alpha particle and the heavy nucleus. That is,
1/2 mv² = 1/4π?￢ﾂﾀ . qαZe / r₀
where r₀ is the distance of closest approach
r₀ = 2/4π?￢ﾂﾀ . qαZe / mv²
r₀ ∞ Ze ∞ qα ∞ 1/m ∞ 1/v²
Hence option (c) is correct.
Related Questions: - A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
- Two sources P and Q produce notes of frequency 660 Hz each.
- A plane electromagnetic wave of frequency 20 MHz travels through a space along
- For principal quantum number n=3, the possible values of orbital quantum number
- A freely suspended bar magnet aligns itself in
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A resistor 30Ω, inductor of reactance 10 Ω and capacitor of reactance 10 Ω
- Two sources P and Q produce notes of frequency 660 Hz each.
- A plane electromagnetic wave of frequency 20 MHz travels through a space along
- For principal quantum number n=3, the possible values of orbital quantum number
- A freely suspended bar magnet aligns itself in
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply