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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two identical cells of the same e.m.f. and same internal resistance
- If the focal length of objective lens is increased, then magnifying power of
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- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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