| ⇦ |
| ⇨ |
An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
Related Questions: - For a given velocity, a projectile has the same range R for two angles of projection.
- The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- Two thin lenses when placed in contact, then the power of combination is +10 D.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a given velocity, a projectile has the same range R for two angles of projection.
- The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
- Two slits in Young’s experiment have widths in the ratio 1:25. The ratio of intensity
- A thin circular ring of mass M and radius R rotates about an axis through its centre
- Two thin lenses when placed in contact, then the power of combination is +10 D.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply