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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If c is the velocity of light in free space, the time taken by light to travel
- A stone thrown into still water, creates a circular wave pattern moving radially
- A particle is under two mutually perpendicular simple harmonic motions
- Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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