⇦ | ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An alternating voltage e=200s in100t is applied to a series combination
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An alternating voltage e=200s in100t is applied to a series combination
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
- Two thin dielectric slabs of dielectric constants K₁ and K₂, (K₁ < K₂) are inserted
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply