3 persons are initially at the 3 corners of an equilateral triangle

3 Persons Are Initially At The 3 Corners Of An Physics Question

3 persons are initially at the 3 corners of an equilateral triangle whose side is equal to d. Each person now moves with a uniform speed v in such a way that the first moves directly towards the second and second directly towards the 3rd and 3rd directly towards the first. 3 persons will meet after a time equal to

Options

(a) d/v s
(b) 2d/3v s
(c) 2d/v√3 s
(d) d/v√3 s

Correct Answer:

2d/3v s

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. A person wants a real image of his own, 3 times enlarged. Where should he stand
  2. If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
  3. In Young’s double slit experiment, for which colour the fringe width is the least
  4. The magnetic lines of force inside a bar magnet
  5. CO₂ laser uses

Topics: Motion in Straight Line (93)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on 3 persons are initially at the 3 corners of an equilateral triangle

  1. D=UT+1/2AT2
    U=0 (GIVEN)
    D=1/2AT2
    2D/A=T2

    V2=U2+2AS (3PERSONS)
    (U=0)
    (3V)2==2AS
    9V2/2D=A
    2D/A=T2
    2D*2D/9V2==T2
    T==2D/3V

Leave a Reply

Your email address will not be published.


*