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3 persons are initially at the 3 corners of an equilateral triangle whose side is equal to d. Each person now moves with a uniform speed v in such a way that the first moves directly towards the second and second directly towards the 3rd and 3rd directly towards the first. 3 persons will meet after a time equal to
Options
(a) d/v s
(b) 2d/3v s
(c) 2d/v√3 s
(d) d/v√3 s
Correct Answer:
2d/3v s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A tuned amplifier circuit is used to generate a carrier frequency of 2 MHz
- Surface tension of water will be minimum at
- A monoatomic gas is suddenly compressed to (1/8)th of its initial volume adiabatically.
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
- A bullet of mass m moving with velocity v strikes a block of mass M at rests
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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D=UT+1/2AT2
U=0 (GIVEN)
D=1/2AT2
2D/A=T2
V2=U2+2AS (3PERSONS)
(U=0)
(3V)2==2AS
9V2/2D=A
2D/A=T2
2D*2D/9V2==T2
T==2D/3V