| ⇦ | 
| ⇨ |
A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4×10⁻¹³ N. The frequency of revolution of the proton is about
Options
(a) 0.08×10⁸ cps
(b) 4×10⁸ cps
(c) 8×10⁸ cps
(d) 12×10⁸ cps
Correct Answer:
0.08×10⁸ cps
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If vₑ is escape velocity and vₙ is orbital velocity of a satellite
- Two parallel beams of positron moving in the same direction will
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- A body is thrown vertically upward in air when air resistance is taken into account
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If vₑ is escape velocity and vₙ is orbital velocity of a satellite
- Two parallel beams of positron moving in the same direction will
- A hemispherical bowl of radius R is rotating about its axis of symmetry
- If 10000 V is applied across an X-ray tube, what will be the ratio of de-Broglie
- A body is thrown vertically upward in air when air resistance is taken into account
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply