| ⇦ | 
| ⇨ |
The point of suspension λ of a simple pendulum with normal time period T₁ is moving upward according to equation y=kt² where k=1 m/s². If new time period is T² the ratio T₁²/T₂² will be
Options
(a) (2/3)
(b) (5/6)
(c) (6/5)
(d) (3/2)
Correct Answer:
(6/5)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Length of a string tied to two rigid supports is 40 cm. Maximum length
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- The equivalent resistance of two resistors connected in series is 6 Ω
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- If the band gap between valence band and conduction band in a material is 5.0 eV,
- The equivalent resistance of two resistors connected in series is 6 Ω
- A satellite in a circular orbit of radius R has a period of 4 hours. Another satellite
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply