| ⇦ | 
| ⇨ |
The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3. The time period of pendulum will be
Options
(a) √2 T
(b) T/√2
(c) √3/2 T
(d) 2/3 T
Correct Answer:
2/3 T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - During an adiabatic process, the cube of the pressure is found to be inversely
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- The work done in which of the following processes is equal to the change in internal energy
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- During an adiabatic process, the cube of the pressure is found to be inversely
- If in a L-R series circuit the power factor is 1/2 and R=100Ω, then the value of L is,
- The work done in which of the following processes is equal to the change in internal energy
- The r.m.s speed of the molecules of a gas in a vessel is 400 m/s
- A body is moving in a vertical circle. The string must remain taut at the highest point
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply