| ⇦ |
| ⇨ |
The period of a simple pendulum inside a stationary lift is T. The lift accelerates upwards with an acceleration of g/3. The time period of pendulum will be
Options
(a) √2 T
(b) T/√2
(c) √3/2 T
(d) 2/3 T
Correct Answer:
2/3 T
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- A man of 50 kg mass is standing in a gravity free space at a height
- The position vector of a particle R as a function of time is given by
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
- A man of 50 kg mass is standing in a gravity free space at a height
- The position vector of a particle R as a function of time is given by
- A spherical liquid drop of radius R is divided into 8 equal droplets. If the surface
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply